What is the optimal ratio of height to radius for a cone with minimum cost?

  • Thread starter BayernBlues
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In summary, the conversation is about solving a problem involving cost and dimensions using calculus. The equation for cost is given, and the derivative is found to be equal to zero when r = h, which is the final solution. The steps are briefly explained for verification.
  • #1
BayernBlues
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Homework Statement



http://img128.imageshack.us/img128/3923/12mx7.png

Homework Equations





The Attempt at a Solution



c=0.06(pie)r^2+0.06(pie)r(k/pie(r^2))

c'=0.06(pie)r - 0.06kr^-2
r^3=k^1/3 / (pie^1/3)

h/r= 1/1

I'm not sure if what I did here is right. I didn't put all the steps up there.
 
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  • #2
ANSWER DIRECT FROM INDIA

yup you have the right answer r/h does = 1

if you briefly want the steps just to check

COST = 0.12*(pie)*r*h + 0.06*(pie)*r^2

find derivative U get

-(K * 0.12)/(r^2) + 0.12*(pie)*r

equate this derivative to zero

thus -K + (pie)*(r^3) = 0

THUS (pie)*(r^3) = K


but K = (p)*(r^2)*h

thus r = h
:wink::wink::wink::wink::wink::wink::wink::wink::wink:
 

FAQ: What is the optimal ratio of height to radius for a cone with minimum cost?

1. What is a "Cone/Cost Max/Min Question"?

A "Cone/Cost Max/Min Question" is a type of problem in mathematics where the goal is to find the maximum or minimum value of a cone's volume or surface area, given a specific cost constraint. This type of question is commonly used in optimization problems in calculus and is often seen in real-world applications such as finding the most cost-effective packaging for a product or the optimal shape for a storage container.

2. How do you solve a "Cone/Cost Max/Min Question"?

To solve a "Cone/Cost Max/Min Question", you will need to use the derivative of the cone's volume or surface area formula with respect to the variable that represents the cone's dimensions (such as its height or radius). You will then set the derivative equal to zero and solve for the variable to find the critical points. Finally, you will use the critical points to determine the maximum or minimum value of the cone's volume or surface area.

3. What is the purpose of a "Cone/Cost Max/Min Question"?

The purpose of a "Cone/Cost Max/Min Question" is to find the optimal values for a cone's dimensions that will result in the maximum or minimum volume or surface area, given a specific cost constraint. This type of problem is useful in real-world scenarios where cost is a factor, as it helps to determine the most efficient use of materials.

4. What are some common applications of "Cone/Cost Max/Min Questions"?

"Cone/Cost Max/Min Questions" have various applications in real-world scenarios, such as determining the most cost-effective shape for packaging, finding the optimal dimensions for a storage container, or maximizing the volume of a cone-shaped container while minimizing its surface area.

5. What are the key concepts needed to solve "Cone/Cost Max/Min Questions"?

To solve "Cone/Cost Max/Min Questions", you will need to have a good understanding of calculus, particularly optimization techniques and related rates. You should also be familiar with the formula for the volume and surface area of a cone, as well as the concept of cost constraints and how they relate to optimization problems.

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