- #1
tua28494
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Homework Statement
What is the pH of a saturated Zn(OH)2 solution?
Ksp = 1.2 x 10^-17
Homework Equations
Ksp = [Zn2+] [OH-]^2
Zn(OH)2 <----> Zn2+ + 2OH-
pOH = -log [OH-]
pH = 14- pOH
The Attempt at a Solution
Ksp = 1.2 x 10^-17 = [Zn2+] [OH-]^2
Zn(OH)2 <----> Zn2+ + 2OH-
- x +x +2x
1.2 x 10^-17 = [x][2x]^2 = 4x^3
x = 1.4 x 10^-6 M
[OH-] = 2x = 2.8 x 10^-6 M
pOH = - log 2.8 x 10^-6 = 5.5
pH = 14 - 5.5 = 8.5
Again I am learning this on my own and do not have a solution manual to the textbook I am using. So just s quick check would be greatly appricated. Thank you for your time.