- #1
jordanl122
- 14
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Two parallel plates having charges of equal magnitude but opposite sign are separated by .12 m. Each plate has a surface charge density of 36 nC/m^2. Determine the potential difference between the plates.
I have to admit I am at a bit of a loss on how to answer this
(lettings S represent the integral sign)
I know Delta V = -SEds
and that E is constant so
Delta V = -ESds so delat V = -Ed
but I am not sure how to find E, I know sigma =Q/A
and I don't see how Gauss' law could really work here
any light someone can shed would be greatly appreciated.
I have to admit I am at a bit of a loss on how to answer this
(lettings S represent the integral sign)
I know Delta V = -SEds
and that E is constant so
Delta V = -ESds so delat V = -Ed
but I am not sure how to find E, I know sigma =Q/A
and I don't see how Gauss' law could really work here
any light someone can shed would be greatly appreciated.