- #1
jaus tail
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Homework Statement
Find power of signal A u(t)
A is constant like 5, 6 some value.[/B]
Homework Equations
Power is integration over -T/2 to +T/2 of [x(t)]2 dt
The whole divide by T
The Attempt at a Solution
Power is integration over -T/2 to +T/2 of [A u(t)]2dt[/B]
The whole divide by T
So 1/T integral A2 dt...integral limits are -T/2 to +T/2
This comes as 1/T A2 integral dt
integral dt is t. limits are -T/2 to +T/2
so integral dt = [T/2 - ( -T/2) ] which becomes T
so Poewr is 1/T * A2 * T
which gives A2
But book answer is A2 /2
Where did the divide by 2 come from?