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Dick
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YODA0311 said:I understand where both you are coming from now. I guess it was easier to read from a textbook and follow the examples. However the actual question is "in how many ways can three aces and two kings be drawn?"
So i figured out how 1 hand of 3 aces and 2 kings can be arranged=10
I found out how many ways 3 aces can be drawn=24
I found out how many ways 2 kings can be drawn=12
If I were to multiply both the 24 and 12= 288, then I should multiply 288 by the 10(arrangements per hand)
That would equal 2880, thus there are 2880 ways 3 aces and 2 kings can be drawn. Is that sound about right?
And you can also get the same probability answer without considering ordering. The number of unordered ways to pick the cards is C(52,5). The number of unordered ways to pick three kings is C(4,3) and two aces is C(4,2). So C(4,3)*C(4,2)/C(52,4) is the same as your 2880/311875200. That would be the more popular way to solve the probability problem.