What is the process for calculating stress on a torus in a high pressure vessel?

In summary, the novice has attempted to calculate the stress on a torus in vacuum filled with air at pressure P. Summing the forces in the radial direction yields the radial stress of 1/2(r+dr)d\psi. The area between R_{rt} and R_{rb} is found, and the tangential stresses in the hoop and longitudinal are found to be sin(dx) and cos(dx), respectively.
  • #1
sid_galt
502
1
I am a novice at stress analysis. For my competition, I need to calculate the stress on a torus in vacuum filled with air at pressure P.

Here's is what I have managed to do. I have attached an image below.

The torus section is an angular section of a curved cylinder. Its angular dimensions are [tex]d\psi[/tex] in reference to the torus cross section at an angle [tex]\psi[/tex] to the horizontal and [tex]d\theta[/tex] in reference to the center of the torus. The major radius of the torus is R and the minor Radius is r.

Summing the forces in the radial direction
[tex]
\displaystyle\frac{1}{2}(r+dr)d\psi[R-rcos(\psi+d\psi)+R-rcos\psi]d\theta*\sigma_r - \displaystyle\frac{1}{2}dr[R-rcos(\psi+d\psi)+R+drcos\psi-rcos(\psi+d\psi)]d\theta*\sigma_{t1}+\displaystyle\frac{1}{2}\pi[(r+dr)^2-r^2]d\theta*\sigma_{t2}=0
[/tex]

Here [tex]\sigma_{t1}[/tex] is the tangential stress with reference to the cross section of the torus and [tex]\sigma_{t2}[/tex] is the tangential stress with reference to the center of the torus and [tex]\sigma_r[/tex] is the radial stress.
[tex]
\displaystyle\frac{1}{2}(r+dr)d\psi[R-rcos(\psi+d\psi)+R-rcos\psi]d\theta[/tex] is the area between [tex]R_{rt}[/tex] and [tex]R_{rb}[/tex](See figure)
[tex]
\displaystyle\frac{1}{2}dr[R-rcos(\psi+d\psi)+R+drcos\psi-rcos(\psi+d\psi)]d\theta[/tex] is the area between [tex]R_{rt}[/tex] and [tex]R_{lt}[/tex]

Am I correct upto this point? If I am, how do I process further?
 

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  • #2
Can anyone help please?
 
  • #3
Even for someone with experience, you have picked a problem that is not so trivial. :biggrin: Out of curiosity, have you reviewed the solution for a straight pipe or spherical vessel. That should give you an idea the basic theory.

The radial stress is easy. Since the system is in equilibrium, the inside radial stress = gas pressure, and the outside in a vacuum must = zero. That's pretty straight forward.

Finding the tangential stresses in the hoop and longitudinal (wrt azimuthal axis) is not so easy.

Give me some time, but if anyone else wants to jump in, they are more than welcome. :biggrin:

This type of problem would be encountered in the internal stresses of an elbow bend of a pipe.
 
  • #4
Thank you for the reply.

Astronuc said:
Out of curiosity, have you reviewed the solution for a straight pipe or spherical
vessel. That should give you an idea the basic theory.

Yes, I have done that.
 
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  • #5
I'll work on this, but it's not often I work with toroidal coordinates.

I don't think you want terms like cos (x + dx).
 
  • #6
Astronuc said:
I'll work on this, but it's not often I work with toroidal coordinates.

Thank you

I don't think you want terms like cos (x + dx).

Since [tex]\lim_{x\rightarrow 0} cos x = 1 - \lim_{x\rightarrow 0} sinx[/tex],
[tex]
cos (x+dx) = cosxcosdx - sinx sindx = cos x (1-sindx) - sinx sin dx = cos x (1 - dx) - sin x dx[/tex]

because for extremely small angles dx, sin dx = dx.

Provided that the equation is correct, can this substitution work?
 
  • #7
With respect to cos (x + dx), I was thinking along the lines of your latex.

Bascially, cos (dx) ~1 and sin (dx) ~ dx, but we don't usually see such use of the differential.

In spherical coordinates for examples, on has r sin[itex]\,\theta[/itex] d[itex]\,\phi[/itex], r d[itex]\,\theta[/itex], and dr.

I believe one needs to work in terms of the major and minor radii, R and r respectively, and the azimuthal angle which sweeps around the plane containing the major radius, and the azimuthal ange which sweeps around the plane containing the minor radius/diameter. One also needs the wall thickness, t, so the wall extends from r to r+t when measured from the toroidal axis.

I think I have an idea on this, but I have to work throught the gory details. :biggrin:
 
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  • #8
Rationale and solution there:

High pressure vessels
by Donald M. Fryer, John F. Harvey
http://books.google.fr/books?id=SZD...page&q="Pressure vessel" Torus stress&f=false

and there in chapter 13 page 804 (Pdf 11/98)
Mechanical Design of Process Equipment.pdf
by Coulson & Richardson

It's done by cutting out a part of the torus with cylindrical symmetry and deducing one stress from the vertical equilibrium. The other stress comes from the equilibrium of a surface element, the stresses acting on one curvature each.
 

FAQ: What is the process for calculating stress on a torus in a high pressure vessel?

What is a torus pressure vessel?

A torus pressure vessel is a type of container or vessel that is shaped like a doughnut or ring. It is used to store or contain pressurized fluids or gases.

What is stress in a torus pressure vessel?

Stress in a torus pressure vessel refers to the internal forces acting on the vessel's material due to the applied pressure from the contained fluid or gas. This stress can cause deformation or failure of the vessel if it exceeds the material's strength.

What factors contribute to stress in a torus pressure vessel?

The main factors that contribute to stress in a torus pressure vessel include the internal pressure of the contained fluid or gas, the vessel's geometry and material properties, and any external loads or forces applied to the vessel.

How is stress calculated in a torus pressure vessel?

Stress in a torus pressure vessel can be calculated using various engineering equations and principles, such as the hoop stress equation, the Lamé equations, and the Tresca and von Mises yield criteria. These calculations take into account the vessel's geometry, material properties, and internal and external forces.

What are the potential dangers of stress in a torus pressure vessel?

If the stress in a torus pressure vessel exceeds the material's strength, it can lead to deformation, leakage, or even catastrophic failure. This can result in serious safety hazards and potential damage to equipment and property. Regular inspection and maintenance of pressure vessels is crucial to ensure they can safely withstand the stress they are designed for.

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