What is the Proper Subspace Hierarchy in a Vector Space with Infinite Subsets?

In summary, the conversation discusses the proof of U(W_i) (i from 1 to infinity) being a proper subspace of V, given that {W_1,W_2,W_3,...} is a collection of proper subspaces of V, and W_i is a subset of W_(i+1) for all i. While the attempt at a solution uses induction to prove that W_i (i from 1 to n) is a proper subset of V, it is unclear how to show that U(W_i) (i from 1 to infinity) is also a proper subset of V. The conversation also explores the idea of defining V as the union of the W's, but this is proven to be a
  • #1
mathboy
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Homework Statement


Let {W_1,W_2,W_3,...} be a collection of proper subspaces of V (i.e. W_i not=V) such that W_i is a subset of W_(i+1) for all i. Prove that U(W_i) (i from 1 to infinity) is a proper subspace of V

The Attempt at a Solution


I've already proven that U(W_i) is a subspace of V, so I only need to show that U(W_i) not= V. I've used induction but that only proves that W_i (i from 1 to n) is a proper subset of V, not U(W_i) (i from 1 to infinity). How do I show that U(W_i) (i from 1 to infinity) is a proper subset of V? I'm familiar with infinite set theory stuff (axiom of choice, etc...), but I don't know how to use it here. I could not use dimensions to help me because infinity minus a number is still infinity. Should I use the complement subsets of W_i?
 
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  • #2
Why can't you DEFINE V to be the union of the W's. Doesn't that V meet all of your premises? But the union of the W's now IS V. I don't see how you could prove the union is a proper subspace.
 
  • #3
V is given. I cannot give it any definition. {W_1,W_2,W_3,...} is defined to be a collection of proper subspaces of V. I can define Y to be the union of the W's, but then I have to show that Y is a proper subset of V.
 
  • #4
I'm pointing out that Y is a counterexample to what you are trying to prove. So what you are trying to prove can't be true for all V.
 
  • #5
Or maybe there is something you haven't told us about V. Does it have some sort of completeness property?
 
  • #6
For a specific counterexample, let V be the vector space of all polynomials. For every n, let Wn be the subspace of all polynomials of degree less than or equal to n. I believe that satisfies the conditions. The union of all such spaces is V itself.
 

FAQ: What is the Proper Subspace Hierarchy in a Vector Space with Infinite Subsets?

What is a subspace?

A subspace is a subset of a vector space that is itself a vector space. This means that it must satisfy the three properties of a vector space: closure under addition, closure under scalar multiplication, and containing the zero vector.

How do you prove that a subset is a subspace?

To prove that a subset is a subspace, you must show that it satisfies the three properties of a vector space: closure under addition, closure under scalar multiplication, and containing the zero vector. You can also prove this by showing that the subset is a linear combination of a set of vectors that span the vector space.

Can a subspace have a dimension greater than the vector space it is a part of?

No, the dimension of a subspace must always be less than or equal to the dimension of the vector space it is a part of. This is because a subspace is a subset of the vector space and cannot have more basis vectors than the vector space itself.

What is the difference between a proper subspace and an improper subspace?

A proper subspace is a subspace that is strictly smaller than the vector space it is a part of. An improper subspace is a subspace that is equal to the vector space it is a part of. In other words, an improper subspace is a subspace that contains the entire vector space.

Can a subspace be infinite-dimensional?

Yes, a subspace can be infinite-dimensional if the vector space it is a part of is also infinite-dimensional. This means that the subspace has an infinite number of basis vectors, which are linearly independent and span the subspace.

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