- #1
shoshuban
- 3
- 0
I am studying in IGCSE and I learned simple techniques to find, say, approximate change in Area of a circle for a small change in its radius, making use of :
δy/ δx ≈ dy/dx .
or δA/ δr ≈ dA/dr .
or δA ≈ dA/dr x δr
so what I basically have to do is find the derivative of A ( πr2 ) , which is 2πr.
then I multiply that with the small change in radius, δr to get the approximate change in area, δA.
But my question here is, why need all of this at all, when I can simply put the old and new values of r in the original equation of A ( πr2 ) and find the exact difference by subtracting :
Change in A = π(rinitial)2 - π(rfinal)2
Why go for calculus to find an approximate value while we can easily get the accurate value without calculus?
δy/ δx ≈ dy/dx .
or δA/ δr ≈ dA/dr .
or δA ≈ dA/dr x δr
so what I basically have to do is find the derivative of A ( πr2 ) , which is 2πr.
then I multiply that with the small change in radius, δr to get the approximate change in area, δA.
But my question here is, why need all of this at all, when I can simply put the old and new values of r in the original equation of A ( πr2 ) and find the exact difference by subtracting :
Change in A = π(rinitial)2 - π(rfinal)2
Why go for calculus to find an approximate value while we can easily get the accurate value without calculus?