- #1
t0mm02
- 49
- 0
- Homework Statement
- PV panel surface area
- Relevant Equations
- Wp = ηpvGBA from Equation (11) above, where
ηpv is module efficiency (18.4%)
GB is solar irradiance (3.8)
A is the PV module surface area
Hello everyone, I am trying to do some calculations for the energy output of a solar farm that I am designing as my dissertation. However, when I trie to calculate the following formula:
Wp = ηpvGBA from Equation (11) above, where:
ηpv is module efficiency (18.4%)
GB is solar irradiance (3.8)
A is the PV module surface area
I am left wondering what the PV module surface area is. Is it the area for one panel or the area that it takes all the PV panels that I would be using?
These are the dimensions for my PV panel:
This is the area for my PV panel:
However, in the example where I have taken that formula from this is the information:
From the irradiance values of a given period in [61], the GHI, DHI, DNI, and ambient temperature for Oxford are 7.41, 4.3, 6.5, and 10.3, respectively. The estimated average building energy load is 8.5 kWh per day, while the solar irradiance value obtained from NASA metrological [68] for Oxford is 3.8 kW/m2 . Similarly, we assume that a monocrystalline module of 300 Wp with an efficiency of 18.4% and a surface area of 65 is selected.
Wp = ηpvGBA from Equation (11) above, where:
ηpv is module efficiency (18.4%)
GB is solar irradiance (3.8)
A is the PV module surface area
I am left wondering what the PV module surface area is. Is it the area for one panel or the area that it takes all the PV panels that I would be using?
These are the dimensions for my PV panel:
1,956 mm (L) x 992 mm (W) x 40 mm (T) |
1.940 m² |
However, in the example where I have taken that formula from this is the information:
From the irradiance values of a given period in [61], the GHI, DHI, DNI, and ambient temperature for Oxford are 7.41, 4.3, 6.5, and 10.3, respectively. The estimated average building energy load is 8.5 kWh per day, while the solar irradiance value obtained from NASA metrological [68] for Oxford is 3.8 kW/m2 . Similarly, we assume that a monocrystalline module of 300 Wp with an efficiency of 18.4% and a surface area of 65 is selected.