What is the Range of x for $|x|^{x^2-3x-4}<1$?

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In summary, the inequality $|x|^{x^2-3x-4}<1$ represents a range of values for the variable $x$ that satisfy the condition of being raised to a power less than 1. To solve this inequality, you can use logarithms to rewrite the expression as $x^2-3x-4<0$, factor the quadratic equation, and find the critical points to determine the range of values for $x$. The absolute value signifies that both positive and negative values of $x$ can satisfy the inequality, resulting in a finite number of solutions. The solutions are all real numbers between the critical points, excluding the critical points themselves, and can be represented as an interval, such as $
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anemone
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If the range of values of $x$ that satisfies $|x|^{x^2-3x-4}<1$ is given by $(a,\,b)$, evaluate $b-a$.

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Congratulations to kaliprasad for his correct solution, which is shown below:):

$|x|^{(x-4)(x+1)} \lt 1$

$(x-4)(x+1)> 0$ for $x < -1$ or $x > 4$

$(x-4)(x+1)<0$ for $x > -1$ and $x< 4$

$(x-4)(x+1)=0$ at $x=-1$ or $x=4$

It is true if either

1) $|x| < 1$ and $(x-4)(x+1) > 0$ possible

or

2) $|x| > 1$ and $(x-4)(x+1) < 0$ So we get $a = 1$ and $b = 4$ therefore $b-a = 3$.
 

FAQ: What is the Range of x for $|x|^{x^2-3x-4}<1$?

What is the meaning of the inequality $|x|^{x^2-3x-4}<1$?

The inequality $|x|^{x^2-3x-4}<1$ represents a range of values for the variable $x$ that satisfy the condition of being raised to a power less than 1.

How do I solve the inequality $|x|^{x^2-3x-4}<1$?

To solve this inequality, you can use logarithms to rewrite the expression as $x^2-3x-4<0$. Then, you can factor the quadratic equation and find the critical points to determine the range of values for $x$ that satisfy the inequality.

What is the significance of the absolute value in the inequality $|x|^{x^2-3x-4}<1$?

The absolute value signifies that both positive and negative values of $x$ can satisfy the inequality. This means that the range of values for $x$ will include both positive and negative real numbers.

Can the inequality $|x|^{x^2-3x-4}<1$ have infinite solutions?

No, the inequality $|x|^{x^2-3x-4}<1$ has a finite number of solutions because the range of values for $x$ is restricted by the critical points and the condition of being raised to a power less than 1.

What are the solutions for the inequality $|x|^{x^2-3x-4}<1$?

The solutions for this inequality are all real numbers between the critical points, excluding the critical points themselves. This can be represented as an interval, such as $(-2, 4)$, where the inequality is true for all values of $x$ in this range.

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