rude man said:A reservoir has a constant temperature by definition. So what does that enable you to do in evaluating ∫δQ/T ?
And BTW ∫δQ/T = 1S2 only if evaluated over a reversible path. Otherwise the integral is < entropy change.
theBEAST said:Sorry I meant ∫δQ/T = 1S2,generated.
But if ∫δQ/T = 1S2,gen, then that means S2 - S1 = 2∫δQ/T
rude man said:No it does not. S2 - S1 = ∫δQ/T over a reversible path. S2 - S1 is the entropy change in ONE of the reservoirs. Since you have two reservoirs at two different temperatures T1 and T2 , each has its own S2 - S1.
Have you figured out how that integral is simplified if you're dealing with entropy changes of reservoirs?
Entropy is a measure of the disorder or randomness in a system. It is a concept commonly used in physics, chemistry, and information theory.
Entropy helps us understand the behavior of physical and chemical systems. It is also a key concept in thermodynamics, where it is used to explain the direction and efficiency of energy transfer.
In general, as entropy increases, so does disorder. This is because higher entropy means there are more possible arrangements or configurations of a system, and some of these arrangements may appear random or disordered.
In a closed system, entropy tends to increase over time. This is known as the second law of thermodynamics. However, in an open system, such as the Earth, entropy can decrease locally as long as it is balanced by an increase in entropy elsewhere.
The exact calculation of entropy depends on the system and its properties. In thermodynamics, it is often calculated using the equation S = k ln W, where S is the entropy, k is the Boltzmann constant, and W is the number of microstates (possible arrangements) of the system.