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Homework Statement
A source of light shines through two apertures resulting in an intensity distribution pattern on a viewing screen.
The central bright fringe is called the m=0 or zeroth order maximum.
In the schematic diagram 1, the light source is to the left of the page and the point P represents the position of the second order intensity maximum on the screen. Two rays r1 and r2 are depicted incident at P.
Calculate the separation d of the two apertures, given the wavelength of the light is 600nm, L = 2m, Y = 5cm.
Remember that δ is the path difference between the rays (vectors) r1 and r2.
Hint: We need to be able to relate δ to the order number and the wavelength of the light.
Homework Equations
The Attempt at a Solution
From wikipedia it says that dsinθm = mλ
I assume I need mλ to find out separation d of the two apertures.
λ = 600nm, L = 2m, Y = 5cm
m = 0
I'm not sure how to comprehend the wavelength.
I really need someone to explain what I need to do here.
Any help would be grand!