What is the significance of centripetal force in the period of a pendulum?

In summary, the period of a pendulum is not constant, but increases as the angle of disturbance increases. The formula used to calculate the period is based on the equation of motion for a mass rotating about a point with a restoring force. This approximation is accurate for angles less than 23 degrees, but becomes inaccurate for angles greater than that.
  • #1
phlegmy
120
0
hey guys i think its well know the period of a pendulum is 2*pi*root(l/g)
which works fine except!...
I've written a small program to model how the bob of a pedulum moves, due to the net forces experienced by it, namely the tension in the wire which is the result of the bobs weight and the centripedal force due to is angular velocity. and the results my prog has spat out are interesting

*when the bob is initially disturbed from its zero position by a very small angle the period is indeed matched my 2*pi*root(l/g)

however
when the bob is initally disturbed by a significant angle (anything from 10 to 89.9 degrees) the period returned by the program is larger than
2*pi*root(l/g)

also the larger the inital disturbance the longer the period becomes.

now what i really want to know is have i made a mistake in my programming!
or
is the reason for the period not agreeing with 2*pi*root(l/g), that the derivation of this formula does not include centripedal force as its assuming it to be so small, due to angular velocity being small, due to the initial disturbace being so small?
and if so then why don't they tell you that in school or college!

all replies appreciated
 
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  • #2
The period of the pendulum is independent of the initial angle only for tiny opening angles.
 
  • #3
The approximation gives 1% deviation at an angle of 23 degrees.
 
  • #5
wow thanks for the quick replies
good to hear that the problem may not be with my programme
as for 1% deviation for a 23 degree starting angle
i see this increase is given by the formula in the link and the ratio of the period given by the small angle formula and this one, is independant of the length of the pendulum
but...
my prog gives a period of +3% for a length of .5 meters
of +3% for a length of 2 metres
and of +3% for a length of 20m
all for a starting angle of 23 degrees

so I'm guessing the approximation formula is pretty accurate at +1% for 23 degrees. so where then am i going wrong
i've included the weight and the centripedal force as (and resulting tension) as the only influences on the bob of the pendulum, is there anything I'm leaving out (i know friction, but I'm assuming the approximation formula does not count on this)
 
  • #6
What method are you using in your numerical scheme?
 
  • #7
the programme works on a loop
each loop advancing time by 5 milliseconds

1>i start with the horizontal displacement of the bob and angular velocity (0)

2>from this and knowing length i find vertical displacement

3>then from the angle of the bob and its angular velocity i get tension in wire

4>from this i get the horizontal force on the bob

5>its subsequent horizontal veloity after 5ms

6>its subsequent horizontal postion after 5ms

7>the new vertical positon from this new horizontal position

8>the new angular velocity from its new position and last position

9>the new tension in the wire from its position and angular velocity


then back to step 3 and reiterate ad infinitum recording the position of the bob and the "time" at each iteration
 
  • #8
The problem is not with the program.

The formula for the period of a pendulum is actually derived from the equation of motion of a mass rotating around a point in the presence of a restoring force. In deriving this result however, the small angle approximation (i.e. sin(x) = x) is made, making the equation inaccurate for large angles.

To put it another way, the equation describing the motion of the pendulum is linear, however the system is actually a rotational one. We can, however approximate the rotational system as being linear as long as we keep the angle small, much the same way as the Earth is approximately flat for short distances.

To make your model work for larger angles, you need to use the original equation of motion for a mass rotating about a point with some restoring force.

Claude.
 
  • #9
thanks claude!
thats actually how i approached the problem, with the tension in the "string" of the pendulum being a restoring force twards the point of suspension, i didnt linearise it at all, which is why the classic "small angle" pendulum formula was throwing me a bit. anway I'm happy enough with the programme, I've just gotten the point of suspension of the pedulum to accelerate linearly and its returning usefull info on how the bob will react!

i'm hoping to develop a model of a tower crane for my final year project in mechanical engineering, which will keep the load from swaying when brought to rest, by adjusting the trolly on the boom to counter any oscillations. so i was keen to pin down the dynamics of a pendulum!
thanks everyone!
 
  • #10
A suggestion might be to formulate the problem in terms of the angular displacement from the vertical, and work with transverse force:

i.e. the real eqn. of motion is

[tex]\ddot{\theta} = -\mbox{$\frac{g}{l}$}\sin{\theta},[/tex]

but at least for small angles, you can take that to be

[tex]\ddot{\theta} = -\mbox{$\frac{g}{l}$}\theta,[/tex]

as opposed to the further simplification that:

[tex]\ddot{x} = -\mbox{$\frac{g}{l}$}x,[/tex]

where x is a Cartesian coordinate.
 
Last edited:
  • #11
I would also suggest looking into some of the standard numerical methods, The forth order Runga-Kutta is very good. You would loose the physical significance which your calculations have but gain much in the way of understanding the errors.
 

FAQ: What is the significance of centripetal force in the period of a pendulum?

What is the period of a pendulum?

The period of a pendulum is the amount of time it takes for the pendulum to complete one full swing, from left to right and back again.

What factors affect the period of a pendulum?

The period of a pendulum is affected by the length of the string, the mass of the bob, and the acceleration due to gravity.

How does the length of the string affect the period of a pendulum?

The longer the string, the longer the period of the pendulum. This is because a longer string means a longer distance for the bob to travel, resulting in a slower swing.

What is the formula for calculating the period of a pendulum?

The formula for calculating the period of a pendulum is T = 2π√(L/g), where T is the period in seconds, L is the length of the string in meters, and g is the acceleration due to gravity in meters per second squared.

How can the period of a pendulum be used in real life?

The period of a pendulum has many practical applications, such as timekeeping devices like grandfather clocks and metronomes. It is also used in scientific experiments and to measure the effects of gravity on different planets.

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