- #1
pendesu
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Homework Statement
Given [itex]\overset{\infty}{\underset{n=0}{\sum}}a_{n}(x-a)^{n}[/itex] and [itex]\overset{\infty}{\underset{n=0}{\sum}}b_{n}(x-a)^{n} [/itex] that are in R. Then, [itex]\overset{\infty}{\underset{n=0}{\sum}}a_{n}(x-a)^{n}=\overset{\infty}{\underset{n=0}{\sum}}b_{n}(x-a)^{n} [/itex] if and only if [itex]a_{n}=b_{n} [/itex] for every [itex] n=0,1,2,... [/itex]
The attempt at a solution
(<<) Assume an=bn for every n=0,1,2,...
Then [itex]\overset{\infty}{\underset{n=0}{\sum}}a_{n}(x-a)^{n}=a_{0}+a_{1}(x-a)+...=b_{0}+b_{1}(x-a)+...=\overset{\infty}{\underset{n=0}{\sum}}b_{n}(x-a)^{n} [/itex].
(>>) Now with this direction I am having some issues as the series may not necessarily converge. My attempts have been feeble at best. The problem I have had is that the sums are infinite so I don't think I can use that polynomials are equal if and only if their coefficients are equal. At this point I am thinking about looking at the nth partial sums but I am not sure and just would like any advice.