What is the Significance of the Orbit of P in Sylow's Theorems?

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The discussion focuses on the significance of the orbit of a p-Sylow subgroup P in relation to Sylow's Theorems. It highlights that if M is a subgroup of G containing the normalizer N_G(P), then the index [G:M] is congruent to 1 modulo p. The action of G on P by conjugation leads to the permutation of subgroups, with the orbit of P containing kp+1 subgroups. This relationship is crucial for understanding the structure of finite groups and the implications of Sylow's Theorems. The exploration of these concepts reveals deeper insights into the properties of group actions and subgroup dynamics.
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Let p be a prime, G a finite group, and P a p-Sylow subgroup of G. Let M be any subgroup of G which contains N_G(P). Prove that [G:M]\equiv 1 (mod p). (Hint: look carefully at Sylow's Theorems.)
 
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since the word N = normalizer occurs, one is led to look at the action on G on p by conjugation. G permutes subgroups of G and we look at the orbit of P. this orbit contains kp+1 subgroups, so the theorem holds if N = M. then what?
 
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