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Bostonpancake0
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Sam, whose mass is 75kg takes off down a 50m high, 10° slope on his jet powered skis. The skis have a thrust of 200N Sam's speed at the bottom of the slope is 40m/s. What is the skis co-effecient of kinetic friction with the ice?
Thought originally to use conservation of energy at top and bottom, then calculate energy loss, then find distance of slope using trigonometry thus allowing me to use w=fxd to find the frictional force acting on skis, then use Fk=μxmass, to co-effecient of kinetic friction, but soon noticed he gained energy down the slope due to his thrust! stuck??
Homework Equations
Thought originally to use conservation of energy at top and bottom, then calculate energy loss, then find distance of slope using trigonometry thus allowing me to use w=fxd to find the frictional force acting on skis, then use Fk=μxmass, to co-effecient of kinetic friction, but soon noticed he gained energy down the slope due to his thrust! stuck??