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Cantworkit
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[SOLVED] linear motion
Skiers leave a ski jump at 28 m/s, at an angle of 9.5 degrees below the horizontal. Their landing zone is a horizontal distance of 55 m from the end of the jumo The ground is contoured at that point so that the skiers trajectories make an angle of only 3 degrees with the ground on landing. What is the slope of the ground in the landing zone?
tan theta = y/x
x = x0 + v0t + 1/2gt^2
y = y0 + y0t + 1/2 gt^2
t = (x - x0)/v0 = (x - x0)/v0cos9.5 = 2s
From here I can solve for the velocity vector at the landing, but I do not see how to solve for the x-y coordinates
Homework Statement
Skiers leave a ski jump at 28 m/s, at an angle of 9.5 degrees below the horizontal. Their landing zone is a horizontal distance of 55 m from the end of the jumo The ground is contoured at that point so that the skiers trajectories make an angle of only 3 degrees with the ground on landing. What is the slope of the ground in the landing zone?
Homework Equations
tan theta = y/x
x = x0 + v0t + 1/2gt^2
y = y0 + y0t + 1/2 gt^2
The Attempt at a Solution
t = (x - x0)/v0 = (x - x0)/v0cos9.5 = 2s
From here I can solve for the velocity vector at the landing, but I do not see how to solve for the x-y coordinates