- #1
EvLer
- 458
- 0
Hello,
so this is what I am stuck on:
In how many different ways can you seat 11 men and 8 women in a row so that no two women are to sit next to each other.
I know it's going to be combination and not permutation and that total number of seating them is 11!*8! but that is as far as I could get
so this is what I am stuck on:
In how many different ways can you seat 11 men and 8 women in a row so that no two women are to sit next to each other.
I know it's going to be combination and not permutation and that total number of seating them is 11!*8! but that is as far as I could get