- #1
Ansuman
- 25
- 0
1.The problem I have been facing is understanding how a straw exactly works ?? I know the general, conventional solution given to this problem by the principle of working of a barometer, but I think it has a serious loophole.
3.They say as a vacuum space is created in the straw due to our breathing actions, hence an extra amount of fluid is required to fill that space up so that the pressure exerted by the fluid given by the equation of {h*density of fluid*acc. due to gravity}, is equal to the atmospheric pressure and the whole condition is in accordance to Pascal's law. But if Mercury lies inside the container and I have a straw some 100 cm long, then will the mercury column rise and stop at 76 cm only, and not above that ?
Infact any liquid will do same, as its density is less than air density, a lesser height of the column of liquid will be required to provide same amount of pressure, so practically, every liquid should rise only a fraction of height of straw. Please explain ??
Any kind of help is appreciated.Thank You
3.They say as a vacuum space is created in the straw due to our breathing actions, hence an extra amount of fluid is required to fill that space up so that the pressure exerted by the fluid given by the equation of {h*density of fluid*acc. due to gravity}, is equal to the atmospheric pressure and the whole condition is in accordance to Pascal's law. But if Mercury lies inside the container and I have a straw some 100 cm long, then will the mercury column rise and stop at 76 cm only, and not above that ?
Infact any liquid will do same, as its density is less than air density, a lesser height of the column of liquid will be required to provide same amount of pressure, so practically, every liquid should rise only a fraction of height of straw. Please explain ??
Any kind of help is appreciated.Thank You