- #1
ChromoZoneX
- 23
- 0
Homework Statement
This was a LAB assignment.
I need to find the specific heat capacity of a given metal (Cu in this case) in water, I have the following observations.
Mass of water: 249.14g = 0.24914 Kg
Initial temperature of water: 18 C
Initial temperature of metal: 100 C
Specific heat capacity of water : 4190 J Kg-1 K-1
Final temperature of mixture in calorimeter is 19 C
Also, the mass of Cu used: 55.89g = 0.05589 Kg
Homework Equations
Just one,
Q = mc[tex]\Delta[/tex]T
-Energy lost by metal = Energy gained by water
The Attempt at a Solution
Applying second eq. ,
(Mass of water)(specific heat cap. water)(Final - Initial temp)= (Mass of Cu)(Specific heat cap.Cu)(final - initial temp)
(0.24914)(4190)(19.5-18)= - (0.05589)(Specific heat cap.Cu)(19-100)
Solving,
Specific heat cap. Cu = 345.88 J Kg^-1 K^-1
However the specific heat capacity of copper should be 380 J Kg^-1 K^-1
Also, I would like to know of it is possible to extend this lab to other stuff (Other than using different metals), given the same apparatus.