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Jeylan
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A 215-g sample of a substance is heated to 330°C and then plunged into a 105-g aluminum calorimeter cup containing 165 g of water and a 17-g glass thermometer at 12.5°C. The final temperature is 35.0°C. What is the specific heat of the substance? (Assume no water boils away.)
Please, can anybody tell me if I'm doing this right? I got to the certain moment and then I got stock. Heelp! c(glass)=0.84, c(aluminum)=0.900, c(water)=4.2 J/g*C
Tinitial (aluminum)=Tinitial (water)=Tinitial (glass thermometr)=12.5 C?
And Tfinal (al)=Tf(water)=Tf(glass)=35C?
Q(substance)=Q(aluminum)+Q(water)+Q(glass)
Q=mc*(Tf-Ti)
But what is the Tinitial for the substance? We know only 330C and this is final?
215*c*(330-Ti)=105*0.900*(35-12.5)+165*4.2*(35-12.5)*17*0.84*(35-12.5)
Please, can anybody tell me if I'm doing this right? I got to the certain moment and then I got stock. Heelp! c(glass)=0.84, c(aluminum)=0.900, c(water)=4.2 J/g*C
Tinitial (aluminum)=Tinitial (water)=Tinitial (glass thermometr)=12.5 C?
And Tfinal (al)=Tf(water)=Tf(glass)=35C?
Q(substance)=Q(aluminum)+Q(water)+Q(glass)
Q=mc*(Tf-Ti)
But what is the Tinitial for the substance? We know only 330C and this is final?
215*c*(330-Ti)=105*0.900*(35-12.5)+165*4.2*(35-12.5)*17*0.84*(35-12.5)