What Is the Speed of an Oscillating Particle at Equilibrium?

In summary: A = 6 meters.Your value of A is not correct. It should be the maximum displacement. Also, make...A = 6 meters.
  • #36
BvU said:
I'm lagging with my slow typing.

Acquiring some "dexterity" with sines and cosines is a good idea.
This exercise helps, but the ##A## and ##\omega## obfuscate things a bit (intentionally, from the point of viewof the exercise composer). For you, practicing with ##x = \sin (\omega t)## is more helpful (i.e. A = 1 and ##\omega = 1##).

Draw a graph of that and a unit circle on the same scale to the left and tadaa: values of x and speed at the angles ##0, {\pi\over 6}, {\pi\over 4}, {\pi\over 3}, {\pi\over 2}, {2\pi\over 3}, {5\pi\over 6}, {\pi} ## and each of these + ##{\pi}## become clear.

See how they all hang together, and also hang together with ##{d^2x\over dt^2} = -x##.

Once you have that internalized, dealing with ##A\ne 0## and ##\omega \ne 0## is a piece of cake and your efficiency in excercises will improve; also: you don't have to remember all that much.
thanks for the advice :)
 
Physics news on Phys.org
  • #37
Welcome. Good luck with your physics binge.

More advice: get some rest when wearing out !
 
  • #38
BvU said:
Welcome. Good luck with your physics binge.

More advice: get some rest when wearing out !
hehe, no rest for me.
 
Back
Top