What Is the Steady-State Solution for This Heat Conduction Problem?

In summary: So, I'm not sure what you mean by integrating it twice.In summary, the conversation discusses finding the steady-state solution of the heat conduction equation with a given set of boundary problems. The problem in question involves the boundary condition ux(0,t)=0, which leads to the need for solving a differential equation using separation of variables. At steady state, the partial derivative with respect to time is equal to 0, and this information is used to solve the problem.
  • #1
Jamin2112
986
12

Homework Statement




In each of Problems 1 through 8 find the steady-state solution of the heat conduction equation ∂2uxx=ut that satisfieds that given set of boundary problems.

...

3. ux(0,t)=0, u(L,t)=0

Homework Equations



Assume u(x,t)=X(x)T(t)


The Attempt at a Solution



2X'' T = X T'

X'' / X = (1/∂2) T' / T = -ß

X'' + ßX = 0,
T + ∂2ßT' = 0.

Since ux(0,t)=0 and u(x,t)=X(x)T(t),

X'(0)T(t)=0 ---> X'(0)=0.

Solving X'' + ßX = 0 like a I would any differential equation,

X(x) = C1cos(√(ß)x) + C2sin(√(ß)x)

--->

X'(x) = -√(ß)C1sin(√(ß)x) + √(ß)C2(cos(√(ß)x)

--->

X'(0)=0= 0 + √(ß)C2 ---> C2=0

--->

X(x) = C1cos(√(ß)x).

Also, u(L,t)=0 ---> X(L)T(t)=0 ---> X(L)=0.

I'm getting somewhere, right?

Since we're talking about a steady-state solution being reached, some function of t and possibly x will disappear, leaving us with just a function v(x) that shows the temperature at any place in the rod.

u(x,t) = v(x) + w(x,t),

limt-->∞ u(x,t) = v(x)


...


Anyhow, I'm sort of stuck. Problem 1 was was easy because it gave me u(0,t)=T1, u(L,t)=T2, just like the examples in the chapter; but this one is throwing me off with the ux(0,t). I'm having trouble putting the pieces together.

Please help, geniuses.
 
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  • #2
At steady state, [itex]\partial T/\partial t=0[/itex]. Why not just integrate [itex]\partial^2 T/\partial x^2=0[/itex] twice and apply the boundary conditions? Or are you required to use separation of variables?
 
  • #3
Mapes said:
At steady state, [itex]\partial T/\partial t=0[/itex]. Why not just integrate [itex]\partial^2 T/\partial x^2=0[/itex] twice and apply the boundary conditions? Or are you required to use separation of variables?

Hmmmmm ... In the textbook example it never has us integrate T''(t)=0 when solving these problems. It does say, however:

Since v(x) must satisfy the equation of the heat equation ß2uxx=ut, we have

v''(x)=0, 0<x<L.
 

FAQ: What Is the Steady-State Solution for This Heat Conduction Problem?

What is heat conduction?

Heat conduction is the transfer of thermal energy through a material or between materials that are in physical contact. It occurs due to temperature differences between the materials and is governed by the laws of thermodynamics.

What causes heat conduction?

Heat conduction is caused by the random movement of molecules within a material. When an object is heated, its molecules gain kinetic energy and vibrate more, colliding with neighboring molecules and transferring thermal energy.

Why is heat conduction important?

Heat conduction is an important phenomenon because it allows for the transfer of thermal energy from hotter areas to cooler areas, leading to temperature equalization. It is essential for many industrial processes, as well as for the functioning of everyday objects like cooking utensils and heating systems.

What factors affect heat conduction?

The rate of heat conduction is influenced by several factors, including the temperature difference between objects, the thermal conductivity of the material, the thickness of the material, and the surface area of contact between the materials.

How is heat conduction calculated?

The rate of heat conduction can be calculated using Fourier's law, which states that the rate of heat flow (Q) is equal to the thermal conductivity (k) multiplied by the temperature difference (ΔT) divided by the thickness of the material (L). This can be expressed mathematically as Q = kΔT/L.

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