- #1
physicsluv
- 14
- 0
Homework Statement
A 1.62 kg object is swung in a vertical circular
path on a string 1.8 m long.
The acceleration of gravity is 9.8 m/s^2.
If the speed at the top of the circle is 5 m/s,
what is the tension in the string when the
object is at the top of the circle?
Answer in units of N
Homework Equations
ac=mv^2/r
Fnet=ma
ac= Centripetal acceleration
The Attempt at a Solution
Ac=mv^2/2ac=5^2/1.8
ac=13.89
(1.63kg=.00162g)
Fnet=ma
Ft+Fg=ma
Ft+(9.8*.00162)=13.89(.00162)
Ft=.006624
But that force of tension does not work :(
Last edited: