- #1
Psyguy22
- 62
- 0
There is a street lamp that weighs 150N. The two wires that are attached to it form at 120°. What is the tension on the wires?
So i drew a diagram. Since the force of gravity acting on the lamp is 150N down, there must be an equal opposite force acting at 150N up.
Then I drew a right triangle and it a 30-60-90. (The 120° was bisected by the upward force).
Then I said that sin(30)=150/T. Then T=150/sin(30) which equals 300N. Is this right?
So i drew a diagram. Since the force of gravity acting on the lamp is 150N down, there must be an equal opposite force acting at 150N up.
Then I drew a right triangle and it a 30-60-90. (The 120° was bisected by the upward force).
Then I said that sin(30)=150/T. Then T=150/sin(30) which equals 300N. Is this right?