What is the value of F_max for an impulse of 6.8 Ns in the given figure?

  • Thread starter Thread starter krej
  • Start date Start date
  • Tags Tags
    Impulse
AI Thread Summary
The discussion revolves around calculating the maximum force (F_max) required to achieve an impulse of 6.8 Ns, based on a provided figure. Initial attempts included integrating force over time and calculating the area of a triangle, both of which yielded incorrect results. The key insight revealed that the time axis is in milliseconds, leading to the correct equation: 4x10^-3 * F_max = 6.8. This adjustment shows that F_max equals 1700 N, highlighting the importance of unit awareness in calculations. The conversation emphasizes the need to carefully consider units in physics problems to avoid errors.
krej
12
0

Homework Statement


In the figure , what value of F_max gives an impulse of 6.8 Ns?
http://img76.imageshack.us/img76/1782/09ex05.jpg

Homework Equations


Integral of F with respect to time equals impulse


The Attempt at a Solution


I tried doing two things, and they were both wrong.

First, i tried the integral of F with respect to time from 0 to 8 = 6.8.
Ft from 0 to 8 = 6.8
F(8) - F(0) = 6.8
F = 6.8/8
F = 0.85
I realize that is wrong though, since the picture they give us isn't of constant force.

So then I tried using the area of a triangle:
Area = (1/2)b*h
Area = (1/2)*8*h
4h = 6.8
h = 6.8/4 = 1.7

So I entered 1.7 into the website, and it said it was wrong. If that didn't work, I have no idea what else I could do to find it.
 
Last edited by a moderator:
Physics news on Phys.org
krej said:

Homework Statement


In the figure , what value of F_max gives an impulse of 6.8 Ns?
http://img76.imageshack.us/img76/1782/09ex05.jpg

Homework Equations


Integral of F with respect to time equals impulse


The Attempt at a Solution


I tried doing two things, and they were both wrong.

First, i tried the integral of F with respect to time from 0 to 8 = 6.8.
Ft from 0 to 8 = 6.8
F(8) - F(0) = 6.8
F = 6.8/8
F = 0.85
I realize that is wrong though, since the picture they give us isn't of constant force.

So then I tried using the area of a triangle:
Area = (1/2)b*h
Area = (1/2)*8*h
4h = 6.8
h = 6.8/4 = 1.7

So I entered 1.7 into the website, and it said it was wrong. If that didn't work, I have no idea what else I could do to find it.
Note that the units on the time axis are miliseconds. Hence, 4x10^-3*Fmax==6.8, Fmax==1700N.
 
Last edited by a moderator:
Oh, wow I didn't notice that at all. I'm too used to it always being in seconds I didn't even think about looking at that. :p

Thanks a lot for your help!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up will act downwards and maximum static friction will act downwards Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top