- #1
Rugile
- 79
- 1
Homework Statement
A ladder of length L = 3 m is leaning against the wall and the angle between ground and and ladder is α=60°. The bottom of the ladder slides at speed Vb = 0.2 m/s. Find the velocity of top of the ladder in respect to
1) wall;
2) bottom of the ladder.
Homework Equations
vx = [itex]\frac{dx}{dt}[/itex]
vy = [itex]\frac{dy}{dt}[/itex]
The Attempt at a Solution
tan(α) = [itex]\frac{y}{x}[/itex], so y(x) = xtan(α). Then we find the derivatives of both sides of equation:
[itex]\frac{dy}{dt}[/itex] =[itex]\frac{d}{dt}xtan(α)[/itex]=>vy1=vx*tan(α)
And so vy1 = 0.2*tan(60°)=0.34 m/s.
So this is the velocity of top part in respect to wall, right? I'm not sure what to do next - to find the velocity in respect to the bottom. Are my calculations right?