- #36
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I did the same thing and got the initial value for theta dot to be -9v/10L, which gives the right answer. My Kinetic energy is:
[tex] T = \frac{2m L^2}{3} (1 + 6 \cos^2 \theta) \dot \theta^2 + 6 L \dot y \cos \theta \dot \theta + 3 \dot y^2[/tex]
But I'm still note sure why it's a good idea to set [itex]p_\theta=0[/itex].
[tex] T = \frac{2m L^2}{3} (1 + 6 \cos^2 \theta) \dot \theta^2 + 6 L \dot y \cos \theta \dot \theta + 3 \dot y^2[/tex]
But I'm still note sure why it's a good idea to set [itex]p_\theta=0[/itex].