What is the Voltage Compliance Range of a Current Source?

In summary, the conversation discussed a homework problem involving a circuit that functions as a current source. It was determined that the circuit is in compliance when the voltage at the top of R_L is between 9V and 10V. The range of load resistors for the circuit to function as a current source was also discussed, with the understanding that it depends on the voltage to R_L and the value of R_L. It was suggested to assume Vcc = 10V for R_L. The concept of voltage compliance was also mentioned, which is the range of output voltage in a constant current power supply where the load regulation is within certain limits. Additionally, the conversation touched on the topic of saturation and how it relates to the transistor in
  • #1
Duave
81
0
Thank you for any help that you can offer.

Did I answer all of the questions correctly and thoroughly? Can you please find any errors, and point them out to me so that I can fix them?

Homework Statement



Show that :

VB = 1.6V
VE = 1.0V
IE = 1.0 mA
IL = 1.0 mA
What is the voltage compliance range of the current source?
For what range of load resistors RL will the circuit function as a current source?

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Homework Equations



RB1/RB2 = {10V - VB}/VB
...................
IL = IE = VB - 0.6/RE
.................
VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
.....................
iout = Vin/RE
............

The Attempt at a Solution



2(a)1

RB1/RB2 = {10V - VB}/VB
..................
8.2k/1.6k = {10V - VB}/VB
.............
5.125VB = {10V - VB}
............
5.125VB + VB = 10V
............
6.125VB = 10V
........
VB = 10V/6.125
.......
VB = 1.63V
......

2(a)2
.......
IL = IE = VB - 0.6/RE
.................
IL = IE = 1.63 - 0.6/1000k
.............
IL = IE = 1.03/1000k
............
IL = IE = 1.03mA
..........
VB - VBE = VE
.............
VE = 1.03V
......
VE/RE = 1.03V/1000k
............
IE = VE/RE = 1.03mA
...............


What is the voltage compliance range of the current source?

The device is in comlpliance when:

VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
...............
VCC - ILRE < Vcomp < {VRE/RE}{VCC/IE}
.................
10V - (0.001A)(1000[ohms]) < Vcomp < {1V/1000[ohms]}{10V/0.001A}
.....................
10V - 1V < Vcomp < 10V
.........
9V < Vcomp < 10V
.........


For what range of load resistors RL will the circuit function as a current source?

The range of load resistors can be found by:

iout = Vin/RE
............
9V/1000[ohms] < Vcomp/RL[ohms] < 10V/1000[ohms]
...................
Your assistance will be greatly appreciated
 
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  • #2
"Compliance range" needs to be better defined.

The circuit is a current source for R_L only if the 8.2K resistor stays at +10V.
Then you can determine how low Vcc to R_L can be before the transistor saturates.

There is in addition a high voltage limit due to the breakdown voltages of the transistor, but that can't be determined with the data you're given.

The last question's answer depends on the voltage to R_L as well as the value of R_L, so I guess assume Vcc = 10V for R_L.
 
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  • #3
rude man said:
"Compliance range" needs to be better defined.

The circuit is a current source for R_L only if the 8.2K resistor stays at +10V.
Then you can determine how low Vcc to R_L can be before the transistor saturates.

There is in addition a high voltage limit due to the breakdown voltages of the transistor, but that can't be determined with the data you're given.

The last question's answer depends on the voltage to R_L as well as the value of R_L, so I guess assume Vcc = 10V for R_L.


@rude man


Thank you. I will make corrections.
 
  • #4
@rude man,


If the compliance voltage is the range of output voltage in a constant current (dc) power supply over which the load regulation is within certain limits, how can I use this knowledge to verify that my last answer is correct. Can the variable load resistor range from 0 to 8k4 ohms. If it is higher than that, what will happen?

Thank you
 
  • #5
If your load is 8000 ohms, what is the collector voltage going to be?
If it's 9000 ohms, what then?

Hint: if the emitter to collector voltage is < about 0.2V the transistor is in saturation.

BTW this is not voltage compliance. It assumes the voltage to RL is a constant +10V.

Voltage compliance is a function of R_L. Try to figure out how low the voltage at the top of R_L can be for a given R_L.
 

FAQ: What is the Voltage Compliance Range of a Current Source?

What is current source analysis?

Current source analysis is a method used in electrical engineering and circuit analysis to determine the behavior and characteristics of a circuit with one or more current sources. It involves using Kirchhoff's current law (KCL) and Ohm's law to calculate the currents at different points in the circuit.

Why is current source analysis important?

Current source analysis is important because it allows us to understand how current flows through a circuit and how different components affect the overall behavior of the circuit. This information is crucial for designing and troubleshooting electrical systems.

What are the key principles of current source analysis?

The key principles of current source analysis include Kirchhoff's current law (KCL), which states that the sum of currents entering a node in a circuit must equal the sum of currents leaving that node; and Ohm's law, which relates the voltage, current, and resistance of a circuit.

How is current source analysis performed?

Current source analysis is typically performed by setting up a system of equations based on Kirchhoff's current law and Ohm's law for the different nodes and branches in a circuit. These equations can then be solved using mathematical techniques such as substitution or elimination.

What are some applications of current source analysis?

Current source analysis can be applied in various fields, including electronics, power systems, and biomedical engineering. It is used to design and analyze circuits, predict circuit behavior, and troubleshoot faulty circuits. It is also used in the design of electrical devices and systems, such as sensors, amplifiers, and power supplies.

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