- #1
Duave
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Thank you for any help that you can offer.
Did I answer all of the questions correctly and thoroughly? Can you please find any errors, and point them out to me so that I can fix them?
Show that :
VB = 1.6V
VE = 1.0V
IE = 1.0 mA
IL = 1.0 mA
What is the voltage compliance range of the current source?
For what range of load resistors RL will the circuit function as a current source?
https://scontent-a.xx.fbcdn.net/hphotos-prn1/t1.0-9/1012267_10151937081750919_819156677_n.jpg
RB1/RB2 = {10V - VB}/VB
...................
IL = IE = VB - 0.6/RE
.................
VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
.....................
iout = Vin/RE
............
2(a)1
RB1/RB2 = {10V - VB}/VB
..................
8.2k/1.6k = {10V - VB}/VB
.............
5.125VB = {10V - VB}
............
5.125VB + VB = 10V
............
6.125VB = 10V
........
VB = 10V/6.125
.......
VB = 1.63V
......
2(a)2
.......
IL = IE = VB - 0.6/RE
.................
IL = IE = 1.63 - 0.6/1000k
.............
IL = IE = 1.03/1000k
............
IL = IE = 1.03mA
..........
VB - VBE = VE
.............
VE = 1.03V
......
VE/RE = 1.03V/1000k
............
IE = VE/RE = 1.03mA
...............
What is the voltage compliance range of the current source?
The device is in comlpliance when:
VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
...............
VCC - ILRE < Vcomp < {VRE/RE}{VCC/IE}
.................
10V - (0.001A)(1000[ohms]) < Vcomp < {1V/1000[ohms]}{10V/0.001A}
.....................
10V - 1V < Vcomp < 10V
.........
9V < Vcomp < 10V
.........
For what range of load resistors RL will the circuit function as a current source?
The range of load resistors can be found by:
iout = Vin/RE
............
9V/1000[ohms] < Vcomp/RL[ohms] < 10V/1000[ohms]
...................
Your assistance will be greatly appreciated
Did I answer all of the questions correctly and thoroughly? Can you please find any errors, and point them out to me so that I can fix them?
Homework Statement
Show that :
VB = 1.6V
VE = 1.0V
IE = 1.0 mA
IL = 1.0 mA
What is the voltage compliance range of the current source?
For what range of load resistors RL will the circuit function as a current source?
https://scontent-a.xx.fbcdn.net/hphotos-prn1/t1.0-9/1012267_10151937081750919_819156677_n.jpg
Homework Equations
RB1/RB2 = {10V - VB}/VB
...................
IL = IE = VB - 0.6/RE
.................
VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
.....................
iout = Vin/RE
............
The Attempt at a Solution
2(a)1
RB1/RB2 = {10V - VB}/VB
..................
8.2k/1.6k = {10V - VB}/VB
.............
5.125VB = {10V - VB}
............
5.125VB + VB = 10V
............
6.125VB = 10V
........
VB = 10V/6.125
.......
VB = 1.63V
......
2(a)2
.......
IL = IE = VB - 0.6/RE
.................
IL = IE = 1.63 - 0.6/1000k
.............
IL = IE = 1.03/1000k
............
IL = IE = 1.03mA
..........
VB - VBE = VE
.............
VE = 1.03V
......
VE/RE = 1.03V/1000k
............
IE = VE/RE = 1.03mA
...............
What is the voltage compliance range of the current source?
The device is in comlpliance when:
VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
...............
VCC - ILRE < Vcomp < {VRE/RE}{VCC/IE}
.................
10V - (0.001A)(1000[ohms]) < Vcomp < {1V/1000[ohms]}{10V/0.001A}
.....................
10V - 1V < Vcomp < 10V
.........
9V < Vcomp < 10V
.........
For what range of load resistors RL will the circuit function as a current source?
The range of load resistors can be found by:
iout = Vin/RE
............
9V/1000[ohms] < Vcomp/RL[ohms] < 10V/1000[ohms]
...................
Your assistance will be greatly appreciated