What is the volume occupied by 0.25mol of chlorine gas

[chitswori]

Homework Statement

Homework Equations

The Attempt at a Solution

 

[chitswori]

tried to use concentration formula
where concentration is given by c=n/v
but the problem is we only given number of moles which is 0.25.can u help me lm lost

 

[Borek]

Have you heard about ideal gas equation?

 

[epenguin]

or the so-called Avogadro's hypothesis?

 

[DeeNos]

The volume occupied by 0.25mol of chlorine gas can be calculated using the ideal gas law, which states that the volume (V) of a gas is equal to the number of moles (n) multiplied by the gas constant (R) and the temperature (T), divided by the pressure (P). Mathematically, this can be represented as V = (nRT)/P.

To calculate the volume, we first need to determine the values of n, R, T, and P. In this case, we know that n = 0.25mol, and R is a constant value of 8.314 J/mol*K. The temperature and pressure values will depend on the conditions under which the gas is being measured.

For example, if we assume that the gas is at standard temperature and pressure (STP), which is 0°C (273.15K) and 1 atmosphere (atm), respectively, then the equation becomes V = (0.25mol * 8.314 J/mol*K * 273.15K)/1atm = 57.6L. Therefore, the volume occupied by 0.25mol of chlorine gas at STP is 57.6L.

It is important to note that the volume will vary depending on the conditions, as stated by the ideal gas law. If the temperature and pressure are changed, the volume will also change accordingly.