blayman5 said:Homework Statement
A spring with spring constant of 29 N/m is
stretched 0.21mfromits equilibrium position.
How much work must be done to stretch it
an additional 0.14 m? Answer in units of J.
Homework Equations
W=-kx(x)/2
The Attempt at a Solution
I solved it and got 0.4263 and it was wrong. does it need to be negative?
blayman5 said:i did ((29)(0.21)(0.14))/2 =0.4263. does it need to be negative?
blayman5 said:Ok so that means it would equal
29*(.21+14)2/2 - 29*(.21)2/2 =1.1368
Thanks
LowlyPion said:That's not quite right.
Additional work = Difference in work = 29*(.21+14)2/2 - 29*(.21)2/2
dleccord said:wait...
wait wait... why is it 14 instead of .14?
Spring force is a force exerted by a stretched or compressed spring. It is a type of elastic force that acts in the opposite direction of the displacement of the spring.
Spring force is calculated using Hooke's law, which states that the force exerted by a spring is directly proportional to the amount of displacement from its equilibrium position. The equation for spring force is F = -kx, where F is the force, k is the spring constant, and x is the displacement.
The strength of spring force is affected by two main factors: the spring constant and the displacement. A higher spring constant or a larger displacement will result in a stronger spring force.
Spring force is used in a variety of everyday objects, such as door hinges, car suspension systems, and trampolines. It is also used in devices like pedometers and shock absorbers.
When multiple springs are connected in series, the total spring force is equal to the sum of the individual spring forces. When multiple springs are connected in parallel, the total spring force is equal to the average of the individual spring forces.