What is u-Substitution and How Do I Use It in Integration?

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In summary, the author is struggling with u-substitution. He understands that it essentially the undoing of the chain rule, but he does not get how to actually go about the procedure. He has this example from his textbook:\int4x\sqrt{x^{2}+1}dxIt says that u=x^2+1 and that du/2=xdx. He asks for help with figuring out how to get the differential of u (i.e., du), where did they get this information, and what to use for u in any given equation. Once he has these to values (u and du), he knows that it is just a matter of taking the integral and
  • #1
chez_butt23
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Homework Statement


I am struggling with u-substitution. I understand that it essentially the undoing of the chain rule, but I don not get how to actually go about the procedure.

I have this example from my textbook:
[itex]\int[/itex]4x[itex]\sqrt{x^{2}+1}[/itex]dx

It says that u=x^2+1 and that du/2=xdx. Where did they get this from? How do I know what to use for u in any given equation. Once I have these to values (u and du) I know that it is just a matter of taking the integral andd then plugging x in for u. Any help is appreciated.
 
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  • #2
chez_butt23 said:

Homework Statement


I am struggling with u-substitution. I understand that it essentially the undoing of the chain rule, but I don not get how to actually go about the procedure.

I have this example from my textbook:
[itex]\int[/itex]4x[itex]\sqrt{x^{2}+1}[/itex]dx

It says that u=x^2+1 and that du/2=xdx.
Do you know how to get the differential of u (i.e., du)?

chez_butt23 said:
Where did they get this from? How do I know what to use for u in any given equation. Once I have these to values (u and du) I know that it is just a matter of taking the integral andd then plugging x in for u. Any help is appreciated.
 
  • #3
If I tske the derivative of u, then that should give me du/dx=something. I then multiply by dx to get du. Is that what you mean?
 
  • #4
That is right, you can treat it just like a fraction. Then isolate dx and substitute it into the original equation along with your U substitution. You'll lean what to substitute U for with experience. Basically, what ever you substitute U for, call it A for you'll end up with [itex]\frac{1}{\frac{d}{dx} A}[/itex]. If you do it right, this factor will cancel with some other x in the integral, leaving you with an integral only in terms of U du.
 
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  • #5
Thank you for the replies. I'm sorry, but I don't understand anything about A. I have never heard of this before. Could you elaborate please?

Also, are there any tricks to figuring out what u is?
 
  • #6
That is the "trick". I said let A represent whatever you substitute for U. Then when you follow the method you'll end up with 1 over A prime. Will post an example, just a sec...
 
  • #7
chez_butt23 said:
...
I have this example from my textbook:
[itex]\int[/itex]4x[itex]\sqrt{x^{2}+1}[/itex]dx

It says that u=x^2+1 and that du/2=xdx. Where did they get this from? ...

chez_butt23 said:
If I take the derivative of u, then that should give me du/dx=something. I then multiply by dx to get du. Is that what you mean?
So, if [itex]\displaystyle u=x^2+1\,,[/itex] then [itex]\displaystyle \frac{du}{dx}=2x\,.[/itex]

Therefore, [itex]\displaystyle du=2x\,dx\,,[/itex] correct ?

Now, divide by 2.
 
  • #8
subsitiution.jpg


I forgot to write dx at the end of original function at top of page, I hope it's still clear.
 
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  • #9
^That right there just solved my problems. Thank you so much for your help everyone I really appreciate it.

One more question though. How do I go about solving u-substitution problems for definite integrals? Is it the same but I plug in values of x and subtract at the end?
 
  • #10
yup.
 
  • #11
One more thing, are there any tricks to realizing if a problem is u-substitution or integration by parts? Or is it merely just a matter of doing one to see if it works?
 

FAQ: What is u-Substitution and How Do I Use It in Integration?

What is u-Substitution?

U-Substitution is a technique used in calculus to simplify the integration of complicated functions. It involves substituting a variable, usually denoted as u, for a portion of the original function in order to make the integration process easier.

When should u-Substitution be used?

U-Substitution is most commonly used when the function being integrated contains a product of two functions, a composition of functions, or a rational function. It can also be used to solve integrals involving trigonometric functions and exponential functions.

How is u-Substitution performed?

The first step in u-Substitution is to identify the portion of the function that can be substituted with a new variable, u. This portion is usually a function within a function, such as sin(x) or e^x. Next, the derivative of u is found and substituted into the integral along with the new variable u. The integral is then solved in terms of u, and the final answer is obtained by substituting back in the original variable.

What are some common mistakes made when using u-Substitution?

One common mistake is forgetting to substitute the derivative of u into the integral. Another mistake is not correctly adjusting the limits of integration when substituting back in the original variable. It is also important to choose the correct u-substitution, as using the wrong variable can make the integration more complicated.

Are there any tips for mastering u-Substitution?

Practice is key when it comes to mastering u-Substitution. Make sure to understand the basic principles and steps involved in the technique, and then try solving a variety of integrals using u-Substitution. It can also be helpful to check your answers using online tools or a calculator to ensure they are correct. Additionally, familiarizing yourself with common u-substitutions and trigonometric identities can make the process easier.

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