- #1
eg2333
- 6
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Ok, so I thought about a derivation for the moment of inertia, but my answer comes out to (3/5)MR^2
Basically, what I did was I considered the sphere as a sum of infinitesimally thin spherical shells.
The moment of inertia for one shell is dI=(r^2)*dm
where dm=(M/V)*4*pi*r^2*dr
where V=(4/3)*pi*R^3
so the equation dI=3*pi*M*r^4*dr when simplified.
Integrating this from 0 to R (Summing up the spherical shells from the center to the edge of the big sphere) gives me (3/5)*M*R^2. The process clearly yields the wrong answer, so I need help seeing where the fault is.
Basically, what I did was I considered the sphere as a sum of infinitesimally thin spherical shells.
The moment of inertia for one shell is dI=(r^2)*dm
where dm=(M/V)*4*pi*r^2*dr
where V=(4/3)*pi*R^3
so the equation dI=3*pi*M*r^4*dr when simplified.
Integrating this from 0 to R (Summing up the spherical shells from the center to the edge of the big sphere) gives me (3/5)*M*R^2. The process clearly yields the wrong answer, so I need help seeing where the fault is.