- #1
dalitwil
- 23
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Suppose that when you ride on your 7.00 kg bike the weight of you and the bike is supported equally by the two tires. If the gauge pressure in the tires is 73.5 lb/in2 and the area of contact between each tire and the road is 7.13 cm2, what is your weight? (in Newtons)
MY WORK:
P(gauge)=P-P(atmosphere)
73.5lb/in2=506765N/m2
P=506765N/m2+101000N/m2
=607765N/m2
F=P/A
=607765/.0713
=8.54e6N
This isn't correct. I also used the fact that the tires are round, so A=pi(d/2)^2 and used that as the area. That wasn't correct either.
I also tried multiplying (both forms of area) by 2, since there is 2 tires. Nope, not correct again.
And finally (all forms of force) I divided my answer by 9.81 since W does equal m*g. Still not correct.
I have been modifying my solutions in a variety of ways, none of which are correct, summerizing (no matter how many times i reread the section) I am not understanding what is going on at all.
Please help me.
MY WORK:
P(gauge)=P-P(atmosphere)
73.5lb/in2=506765N/m2
P=506765N/m2+101000N/m2
=607765N/m2
F=P/A
=607765/.0713
=8.54e6N
This isn't correct. I also used the fact that the tires are round, so A=pi(d/2)^2 and used that as the area. That wasn't correct either.
I also tried multiplying (both forms of area) by 2, since there is 2 tires. Nope, not correct again.
And finally (all forms of force) I divided my answer by 9.81 since W does equal m*g. Still not correct.
I have been modifying my solutions in a variety of ways, none of which are correct, summerizing (no matter how many times i reread the section) I am not understanding what is going on at all.
Please help me.