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1. Homework Statement [/b]
1)for an object of size 0.5 Angstrom, what is the longest-wavelength photon with which it can be observed?
2)for the object of problem 1, what is the smallest-energy electron which can be used to make the measurement?
1)[tex]\Delta[/tex]p x [tex]\Delta[/tex] x [tex]\geq[/tex] [tex] h\ =\ 6.62606876(52)\ \times\ 10^{-34}\ J\ s[/tex]/4(3.142)
2)[tex]\Delta[/tex]E x [tex]\Delta[/tex] t [tex]\geq[/tex] [tex] h\ =\ 6.62606876(52)\ \times\ 10^{-34}\ J\ s[/tex]/4(3.142)
for problem 1,
0.5Angstrom is the wavelength.
i use the equation of E=hf to find the energy.
thn i use 2nd equation above to find [tex]\Delta[/tex] t
i use the [tex]\Delta[/tex] t [tex]\geq[/tex] [(lamda)^2]/4(pi)(speed of light)(delta lamda)
i did find the answer...bt somehow i feel like i did wrong
for problem 2,
i duno where i should start...
i tinking of using equation 2 bt I am not sure...whether energy equation from above is correct
the answer for prob 1 : 0.5Angstrom
the answer for prob 2 : 602eV
1)for an object of size 0.5 Angstrom, what is the longest-wavelength photon with which it can be observed?
2)for the object of problem 1, what is the smallest-energy electron which can be used to make the measurement?
Homework Equations
1)[tex]\Delta[/tex]p x [tex]\Delta[/tex] x [tex]\geq[/tex] [tex] h\ =\ 6.62606876(52)\ \times\ 10^{-34}\ J\ s[/tex]/4(3.142)
2)[tex]\Delta[/tex]E x [tex]\Delta[/tex] t [tex]\geq[/tex] [tex] h\ =\ 6.62606876(52)\ \times\ 10^{-34}\ J\ s[/tex]/4(3.142)
for problem 1,
0.5Angstrom is the wavelength.
i use the equation of E=hf to find the energy.
thn i use 2nd equation above to find [tex]\Delta[/tex] t
i use the [tex]\Delta[/tex] t [tex]\geq[/tex] [(lamda)^2]/4(pi)(speed of light)(delta lamda)
i did find the answer...bt somehow i feel like i did wrong
for problem 2,
i duno where i should start...
i tinking of using equation 2 bt I am not sure...whether energy equation from above is correct
the answer for prob 1 : 0.5Angstrom
the answer for prob 2 : 602eV