- #1
fonz
- 151
- 5
I'm struggling to understand what makes the wheatstone bridge such a good circuit for measuring small resistances. Essentially the bridge is just two voltage dividers and the output voltage is the difference between the two dividers.
Ok so the only advantage I can see over a conventional single voltage divider is that when the instrument being measured is zero, the output voltage will be zero. Which if I am correct is not achievable with a single voltage divider?
So in terms of the accuracy and precision of the measurement at Vout the bridge has virtually no effect it is simply there to provide zero voltage when the instrument is zero?
Thanks
Ok so the only advantage I can see over a conventional single voltage divider is that when the instrument being measured is zero, the output voltage will be zero. Which if I am correct is not achievable with a single voltage divider?
So in terms of the accuracy and precision of the measurement at Vout the bridge has virtually no effect it is simply there to provide zero voltage when the instrument is zero?
Thanks