- #1
UNknown 2010
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An electric pump pulls water at a rate of 0.25 m /s
from a well that is 25 m deep. The water leaves the
pump at a speed of 8.5 m/s.
1. What power is needed to lift the water to the surface?
2.The necessary increase in power the pump to make the water flowing through it quickly 8.5m/s
my answer
1. t= (25^3)\0.25=62500 seconds
P=w\t=Fd\t= ((25)(25))\(62500)=1\10000 W
2. P=FV= (.25)(8.5)=2.125 W
from a well that is 25 m deep. The water leaves the
pump at a speed of 8.5 m/s.
1. What power is needed to lift the water to the surface?
2.The necessary increase in power the pump to make the water flowing through it quickly 8.5m/s
my answer
1. t= (25^3)\0.25=62500 seconds
P=w\t=Fd\t= ((25)(25))\(62500)=1\10000 W
2. P=FV= (.25)(8.5)=2.125 W