- #1
needingtoknow
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Homework Statement
What value of t will make the function = 250?
N(t) = 500 / (1+9e^(-5t))
250 = 500 / (1+9e^(-5t))
The Attempt at a Solution
1 + 9e^-5t = 2
9e^-5t = 1
t = log1/log(-5)(9e)
t = 0
However t = 0 is incorrect because when it is subbed back into the original equation it does not result in 250. How do I solve for the correct value of t?