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Nightrider55
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Homework Statement
A popular pastime is to see who can push an object closest to the edge of a table without its going off. You push the 100 g object and release it 2.20 m from the table edge. Unfortunately, you push a little too hard. The object slides across, sails off the edge, falls 0.500 m to the floor, and lands 25.0 cm from the edge of the table.
If the coefficient of kinetic friction is 0.300, what was the object's speed as you released it?
Homework Equations
y = (1/2)*g*t^2 therefore t = (2*y/g)^(1/2)
x = v2*t therefore x = v2*(2*y/g)^(1/2)
The Attempt at a Solution
I worked everything out and I got 3.60 m/s for the speed when released but my online homework program says "Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures." I checked my work and I am not sure where I went wrong.
Here are the values I got
V2=.7836 m/s velocity when it leaves the table
T(3-2) time it takes to hit the ground once leaving the table=.319 sec
A0=-2.94m/s^2
V0=3.5966
To find V0 I used X1=(-Vox^2)/(2Ax) then solved for Vox any insight as to where I went wrong?