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vkash
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in elevator before cable breakA block of mass m is suspended from the ceiling of a stationary elevator through a spring of spring constant k. suddenly, the cable breaks and the elevator starts galling freely. show that the block now executes a simple harmonic motion of amplitude mg/k in elevator.
mg=kx
in frame of elevator after cable break
F(gravity)+F(pseudo)+F(spring)=0
answering question is not tough but i am interested in other things that will happen with this system.
Will the elevator move with a constant acceleration with respect to a person standing on the surface of earth.? (If mass of block attached to spring and elevator are comparable.)
I think elevator will not move with constant acceleration ; but the center of mass of spring mass plus elevator will move with constant acceleration. since acceleration of spring block is not g (acceleration due to gravity) so elevator will not move with constant acceleration...
How will you define the motion of block after cable breaks (with respect the Earth's frame)?
I can't do this.