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Vismutti
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- TL;DR Summary
- Chemistry behind semiconductor dont make sense. Example adding phosphorous into silicon cause it to lose electron, but at the same time it gains 4, and it ends up being positive. Explanations needed.
This is a confusing subject for me. It's like only getting half of the story. Reading physics but not understanding how it works in chemistry makes it nonsense to me.
Imagine we are creating a silicon-based semiconductor. They have covalent bonds between them, with each silicon atom having four covalent bonds, each containing two electrons.
We add a small amount of phosphor to the other side of the silicon block to make an n-type. Silicon wants to establish the same number of bonds as it does with the other silicon atoms, so it forms them with them. One additional electron in phosphorus will go to the conduction band. This will make it positive because it lost one electron, but how can it be positive while it gains four more shared electrons from silicon? doesn't make sense, does it? Furthermore, phosphor has stronger electronegativity, which means it attracts electrons with greater force, making it even more negative. After all of this, how will it still be positive, rather than some of the silicon atoms?
Now, let's begin to create the p-type on another side of the silicon block with gallium. Gallium tends to lose electrons, but for some reason, it gets one nevertheless, turning it negative and providing room for another electron in silicon's valence shell. The electric band diagram reveals it to be closer to the valence electron, so they may move easily, but it's strange they prefer gallium's shell since silicon is more electronegative and gallium didn't want it to begin with.
Do they teach it this way since behind this explanation there is the fact that there are multiple options to build a semiconductor that has different electronegativities, therefore behaving differently but the same way under electricity? Or does room temperature really excite them so much?
Then, because I don't comprehend p-type and n-type, I can't grasp the combination of them. Somehow, electrons fill some of the holes on the p side, bypassing the positively charged phosphor and its shell and proceeding down to the silicon's shell, and so on.
Imagine we are creating a silicon-based semiconductor. They have covalent bonds between them, with each silicon atom having four covalent bonds, each containing two electrons.
We add a small amount of phosphor to the other side of the silicon block to make an n-type. Silicon wants to establish the same number of bonds as it does with the other silicon atoms, so it forms them with them. One additional electron in phosphorus will go to the conduction band. This will make it positive because it lost one electron, but how can it be positive while it gains four more shared electrons from silicon? doesn't make sense, does it? Furthermore, phosphor has stronger electronegativity, which means it attracts electrons with greater force, making it even more negative. After all of this, how will it still be positive, rather than some of the silicon atoms?
Now, let's begin to create the p-type on another side of the silicon block with gallium. Gallium tends to lose electrons, but for some reason, it gets one nevertheless, turning it negative and providing room for another electron in silicon's valence shell. The electric band diagram reveals it to be closer to the valence electron, so they may move easily, but it's strange they prefer gallium's shell since silicon is more electronegative and gallium didn't want it to begin with.
Do they teach it this way since behind this explanation there is the fact that there are multiple options to build a semiconductor that has different electronegativities, therefore behaving differently but the same way under electricity? Or does room temperature really excite them so much?
Then, because I don't comprehend p-type and n-type, I can't grasp the combination of them. Somehow, electrons fill some of the holes on the p side, bypassing the positively charged phosphor and its shell and proceeding down to the silicon's shell, and so on.