Whats the force of this baseball?

[yeyspaz]

This is a simple problem, but for some reason i can't come up wit the answer. I am i using the wrong formula? A base ball is traveling and strikes a catchers mitt, bringing it to rest. the mitt recoils 11 cm.
m=.14 kg
vi=45 m/s
vf=0 m/s
d=11cm (.11 m)
i used the formula vf^2=vi^2+2ad to get the accelearation the used F=ma for force, but i got 1289N. It seems a little much for a ball, is it right or did i use the wrong formula? please help!

 

[andrewchang]

its right.

 

[quicknote]

Based on the information provided, the force of the baseball can be calculated using the formula F=ma, where F is the force, m is the mass, and a is the acceleration. In this case, the mass of the baseball is 0.14 kg and the acceleration can be calculated using the formula a= (vf-vi)/t, where vf is the final velocity (0 m/s) and vi is the initial velocity (45 m/s). We also need to convert the displacement from centimeters to meters, so d=0.11 m. Plugging these values into the formula, we get:

a=(0-45)/t
0.11=45*t
t=0.0024 s

a=(0-45)/0.0024
a=-18750 m/s^2

Now, we can plug this value for acceleration into the formula F=ma to get the force of the baseball:

F=(0.14 kg)(-18750 m/s^2)
F=-2625 N

Therefore, the force of the baseball is -2625 N, which is a reasonable value for a baseball traveling at 45 m/s and stopping in a short amount of time. It is important to note that the negative sign indicates that the force is acting in the direction opposite of the baseball's motion. It is possible that there may have been a mistake in the calculations or in using the correct formula, but the result is within a reasonable range for a baseball. It is always a good idea to double check your calculations and make sure you are using the correct formula for the given situation.