- #1
davekardle
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What's the volume of water required inside the lock if...
The dimension of the lock is:40 long x 3.5 height x 6 width
allowing 0.5 height.
The ship weights 400T plus 300T(LOAD)
total= 700T
whats the amount of water used per lock allowing allowing 0.5 m from the height?
What if the ship empties its load on the lock ? the density of the load is 755kg/m^3.
Archimedes principle
Mass of water displaced
Mass of water displaced by the boat mass = 700T
VOLUME = 700M^3
Total volume inside the lock allowing 0.5
(3x40x6)m^3 - 700M^3
Is that correct ?
How about if the ship empties its load on the lock ?
Homework Statement
The dimension of the lock is:40 long x 3.5 height x 6 width
allowing 0.5 height.
The ship weights 400T plus 300T(LOAD)
total= 700T
whats the amount of water used per lock allowing allowing 0.5 m from the height?
What if the ship empties its load on the lock ? the density of the load is 755kg/m^3.
Homework Equations
Archimedes principle
Mass of water displaced
The Attempt at a Solution
Mass of water displaced by the boat mass = 700T
VOLUME = 700M^3
Total volume inside the lock allowing 0.5
(3x40x6)m^3 - 700M^3
Is that correct ?
How about if the ship empties its load on the lock ?