When Are the Equivalence and Inequality Met?

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In summary, the conversation discusses proving the inequality EF+FG+GH+HE≥2AC and determining the conditions for when the equivalence can be taken. The participants suggest rearranging four cards in a specific position and then conclude that the equivalence can be taken when points E, F, G, H are midpoints of AB, BC, CD, and DA respectively.
  • #1
Albert1
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Rectangle ABCD ,having fours points$ E,F,G,H $ located on segments AB, BC, CD,and

DA respectively , please prove :

$EF+FG+GH+HE\geq 2 AC $

and determine when the equivalence can be taken ?
 
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  • #2
Re: Ef+fg+gh+he>=2ac

suppose we have another three cards equivalent to figure 1 ,and rearranging these four cards
in a position as shown in figure 2
from figure 2 we see :2AC=AP=HQ< HG+GM+MN+NQ=EF+FG+GH+HE
figure 3 shows the equivalence will be taken when E,F,G,H are midpoints of AB,BC,CD,and DA respectively
2AC=AC+BD=EF+FG+GH+HE
View attachment 1644
 

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FAQ: When Are the Equivalence and Inequality Met?

What does "Prove EF + FG + GH + HE ≥ 2AC" mean?

This statement is an inequality that is used in geometry to prove that the sum of the four sides of a quadrilateral is greater than or equal to twice the length of the diagonal AC.

Why is it important to prove this inequality?

Proving this inequality is important because it helps us understand the relationships between the sides and diagonals of a quadrilateral. It also has practical applications in real-life situations, such as designing structures or calculating distances.

How is this inequality proven?

This inequality can be proven using the Triangle Inequality Theorem and the properties of quadrilaterals. By drawing diagonal AC and creating two triangles, we can use the Triangle Inequality Theorem to show that the sum of the lengths of the four sides is greater than or equal to the sum of the lengths of the two diagonals, which is twice the length of AC.

What types of quadrilaterals does this inequality apply to?

This inequality applies to all types of quadrilaterals, including squares, rectangles, parallelograms, rhombuses, and trapezoids. It is a general inequality that holds true for any quadrilateral, regardless of its shape or size.

Can this inequality be used to prove other geometric properties?

Yes, this inequality can be used to prove other geometric properties, such as the Pythagorean Theorem, the Midpoint Theorem, and the Angle Bisector Theorem. It is a fundamental inequality that is often used in geometry proofs to establish relationships between different parts of a figure.

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