When carring the nonpolar compound

[pietro18]

Homework Statement

When carring the nonpolar compound from nonpolar solvent in water Gibb’s free energy increase by 3,85kJ, the enthalpy decrease by 2,7kJ/mole and 22,5J/K accordingly . To calculate the temperature of solution.



a) 18 C
b) 112oC
c) 27 0C
d) 560C


Hepl PLZ

Homework Equations

The Attempt at a Solution

 

[BvU]

Sure. What do you want to know ?
And: I can only help if you fill in 2 and 3 also, otherwise all I can do is give you the answer and that is useless!
(it's also flagrantly against PF rules and I don't want no trouble with them)

 

[pietro18]

I'd like to know, how to calculate this taks step by step.

Thanks for help.

 

[BvU]

Well, wat are the relevant equations, and what have you done to come toward a solution?

By the way, what does carring mean? Is the problem statement complete ?

 

[HalfLostAndSearching]

I would first clarify any missing information and assumptions in the given context. For example, it is unclear what is meant by "carring" and what specific nonpolar compound and solvents are being referred to. Additionally, the units for enthalpy change should be specified (e.g. kJ/mol or J/g).

Assuming that the compound is being transferred from a nonpolar solvent to water, the positive change in Gibb's free energy suggests that the process is not spontaneous and requires energy input. The negative change in enthalpy suggests that the process is exothermic, meaning heat is released. The positive change in entropy (22.5 J/K) suggests an increase in disorder, which is expected when a nonpolar compound is introduced to a polar solvent like water.

To calculate the temperature of solution, we can use the equation ΔG = ΔH - TΔS, where ΔG is the change in Gibb's free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy. Rearranging this equation to solve for T, we get T = (ΔH - ΔG)/ΔS.

Substituting the given values, we get T = (2.7 kJ/mol - 3.85 kJ/mol)/22.5 J/K = -0.051 K. However, this result is not physically meaningful as temperature cannot be negative. It is possible that there was an error in the given values or in the calculations. Without further information, it is difficult to determine the correct answer to this question.

I would suggest double-checking the given values and units and providing more context for the question. I would also recommend reviewing the calculations and equations used to ensure accuracy.