When gradient is parallel to position vector

In summary: .is it -2ak (ı am not sure)find the unit vector of that and do the dot product of that and the gradiant and see if you get the answer you are looking for.
  • #1
oahsen
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0

Homework Statement



suppose that grad of f(x,y,z) is always parallel to the position vector xi+yj+zk. show that f(0,0,a)=f(0,0,-a) for any a.


The Attempt at a Solution


grad of f= fx(x,y,z)i+fy(x,y,z)j+fz(x,y,z)k ; then gradf (dot) pos.vector = |gradf|*|pos.vector| (since cos(teta)=1 ) ===> however ı could not do anything with this equation and ı have not any other idea...
 
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  • #2
dot product, or cosine of theta

positive if theta is 0, negative if theta is 180 or pi

that tells your max and min slope
 
  • #3
Mathgician said:
dot product, or cosine of theta

positive if theta is 0, negative if theta is 180 or pi

that tells your max and min slope

what should ı do with the max and min slope value?
 
  • #4
oahsen said:
what should ı do with the max and min slope value?

what is the vector from f(0,0,a) to f(0,0,-a)?

find the unit vector of this vector,

and then do the dot product of the unit vector and the gradient vector.
 
  • #5
Mathgician said:
what is the vector from f(0,0,a) to f(0,0,-a)?

find the unit vector of this vector,

and then do the dot product of the unit vector and the gradient vector.

since we do not know f how can we find the vector from f(0,0,a) to f(0,0,-a)?
please be more clear. I do not know perfectly this subject.
 
  • #6
oahsen said:
since we do not know f how can we find the vector from f(0,0,a) to f(0,0,-a)?
please be more clear. I do not know perfectly this subject.

lets call f(0,0,a) point P, and f(0,0,-a) point S

What is vector PS?
 
  • #7
Mathgician said:
lets call f(0,0,a) point P, and f(0,0,-a) point S

What is vector PS?

is it -2ak (ı am not sure)
 
  • #8
find the unit vector of that and do the dot product of that and the gradiant and see if you get the answer you are looking for
 

FAQ: When gradient is parallel to position vector

What does it mean when the gradient is parallel to the position vector?

When the gradient is parallel to the position vector, it means that the rate of change of a function in a particular direction (represented by the gradient) is equal to the direction of movement (represented by the position vector).

How can you determine if the gradient is parallel to the position vector?

To determine if the gradient is parallel to the position vector, you can calculate the dot product of the gradient vector and the position vector. If the dot product is equal to zero, then the vectors are perpendicular and the gradient is not parallel to the position vector.

What is the significance of the gradient being parallel to the position vector?

The significance of the gradient being parallel to the position vector is that it indicates a direction of maximum change for a given function. This can be useful in optimization problems, where finding the direction of maximum change can help determine the most efficient solution.

Can the gradient and position vector ever be parallel?

Yes, the gradient and position vector can be parallel in certain cases. This occurs when the function is constant in a particular direction, meaning there is no change in that direction and the gradient is zero. In this case, any direction can be considered parallel to the position vector.

How does the concept of parallel gradient and position vector relate to vector calculus?

The concept of parallel gradient and position vector is an important aspect of vector calculus, as it allows for the calculation of directional derivatives and optimization in multiple variables. It also helps to understand the relationship between the gradient and level curves/surfaces of a function.

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