When Is Kinetic Energy Equal to Rest Energy for a Proton?

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The discussion focuses on determining the speed of a proton when its kinetic energy equals its rest energy. The relevant equations include the kinetic energy formula K = mc^2(γ - 1) and the rest energy E_0 = mc^2, with γ defined as 1/√(1 - v^2/c^2). The solution shows that setting K equal to E_0 leads to γ = 2, resulting in a speed of v = 0.866c. The approach correctly applies relativistic energy principles, confirming that the calculations are valid for any massive particle, not just protons. The conclusion affirms the accuracy of the method used to find the speed.
mattst88
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Homework Statement



What is the speed of a proton when its kinetic energy is equal to its rest energy?

Homework Equations



K = mc^2(\gamma - 1)
E_0 = mc^2
\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}

The Attempt at a Solution



K = E_0
mc^2(\gamma - 1) = mc^2
\gamma = 2
\frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} = 2
0.5 = \sqrt{1 - \frac{v^2}{c^2}}
0.5^2 = 1 - \frac{v^2}{c^2}
c^2 \sqrt{1 - 0.25} = v^2
v = c \sqrt{0.75} = 0.866 c

Am I right to use relativistic energy? Have I come to the correct answer? Please advise.
 
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correct (for any massive particle, not just the proton)
 

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