- #1
TKay
- 1
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Hello, Forum!
I just registered after seeing you actually help people understand their problems. That's great.
We have (or should have) learned about linearity, substitution and partial integration. However, I don't know when to use which! Could someone also give me a bit of an expanation on this? :(
I have to solve an integral:
x*e^(-3x) dx
My train of thought: I have almost got 2 'basis integrals': x dx and e^x dx. I probably need to substitute to get them to the basic form. But how!
As you see I'm pretty clueless, but what I came up with was:
u = -3x --> u'= -3
v' = x --> v = (x²)/2
However, this leads nowhere. I don't know what to do!
According to derive, the solution is supposed to be:
I sincerely hope someone will be able to show me the light!
Thanks in advance.
PS: Our teacher is really bad at teaching!
I just registered after seeing you actually help people understand their problems. That's great.
We have (or should have) learned about linearity, substitution and partial integration. However, I don't know when to use which! Could someone also give me a bit of an expanation on this? :(
I have to solve an integral:
x*e^(-3x) dx
My train of thought: I have almost got 2 'basis integrals': x dx and e^x dx. I probably need to substitute to get them to the basic form. But how!
As you see I'm pretty clueless, but what I came up with was:
u = -3x --> u'= -3
v' = x --> v = (x²)/2
However, this leads nowhere. I don't know what to do!
According to derive, the solution is supposed to be:
Code:
1 -3x ⎛ x 1 ⎞
⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ - e ⎜⎯⎯⎯⎯⎯⎯⎯⎯⎯ + ⎯⎯⎯⎯⎯⎯ ⎟
2 ⎜ 3·LN(e) 2⎟
9·LN(e) ⎝ 9·LN(e) ⎠
I sincerely hope someone will be able to show me the light!
Thanks in advance.
PS: Our teacher is really bad at teaching!
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