- #1
find_the_fun
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In this video of Laplace transforms the equation \(\displaystyle \lim_{t \to \infty}\frac{te^{-st}}{-s}\) is said to be 0. I'm not sure I agree with the reasoning. It says it's because \(\displaystyle e^t\) grows faster than \(\displaystyle t\); can you treat infinity like that? For example could you say \(\displaystyle \lim_{x \to \infty}\frac{x}{x^2}=0\)? I thought it was undefined because obviously \(\displaystyle \frac{infty}{infty}\) is undefined.
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