- #1
rsq_a
- 107
- 1
A simple question.
Suppose I have [tex]\epsilon^2 y''' - y' = \frac{1}{1+x^2}[/tex].
The goal is to calculate the Fourier transform of [tex]y(x,t)[/tex] where we define,
[tex]\hat{y}(k,t) = F[\phi] = \int_{-\infty}^{\infty} y e^{ikx} ds[/tex]
We're also given that,
[tex]F\left[ \frac{1}{1+x^2} \right] = \pi e^{-|k|}[/tex]
Now we take transforms of both sides:
[tex]\rightarrow F[\epsilon^2 y''' - y] = F[\frac{1}{1+x^2}][/tex]
[tex]\rightarrow -i k^3 \epsilon^2 \hat{y} - ik \hat{y} = \pi e^{|k|}[/tex]
[tex]\rightarrow \hat{y} = -\frac{\pi e^{-|k|}}{ik(1-\epsilon^2 k^2)}[/tex]
The answer, however, is supposed to be:
[tex]\hat{y} = -\frac{\pi e^{-|k|}}{ik(1-\epsilon^2 k)} + 2\pi a \frac{k\delta(k)}{k(1-\epsilon^2 k^2)}[/tex]
where 'a' is some constant.
My question is why? I know it has something to do with an additive constant, but I need someone to be explicit with the mistake.
Suppose I have [tex]\epsilon^2 y''' - y' = \frac{1}{1+x^2}[/tex].
The goal is to calculate the Fourier transform of [tex]y(x,t)[/tex] where we define,
[tex]\hat{y}(k,t) = F[\phi] = \int_{-\infty}^{\infty} y e^{ikx} ds[/tex]
We're also given that,
[tex]F\left[ \frac{1}{1+x^2} \right] = \pi e^{-|k|}[/tex]
Now we take transforms of both sides:
[tex]\rightarrow F[\epsilon^2 y''' - y] = F[\frac{1}{1+x^2}][/tex]
[tex]\rightarrow -i k^3 \epsilon^2 \hat{y} - ik \hat{y} = \pi e^{|k|}[/tex]
[tex]\rightarrow \hat{y} = -\frac{\pi e^{-|k|}}{ik(1-\epsilon^2 k^2)}[/tex]
The answer, however, is supposed to be:
[tex]\hat{y} = -\frac{\pi e^{-|k|}}{ik(1-\epsilon^2 k)} + 2\pi a \frac{k\delta(k)}{k(1-\epsilon^2 k^2)}[/tex]
where 'a' is some constant.
My question is why? I know it has something to do with an additive constant, but I need someone to be explicit with the mistake.